The pair of Intersecting lines in the following are.
A. x-2y=0
3x+4y=20
B. x + 3y = 6
2x - 3y = 1
C. y=2x-2
y = 4x-4
D. x + 2y = 4
2x+4y = 12
Answers
Answer:
Exercise 3.1
1. Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situation algebraically and graphically.
Ans. Let the present age of Aftab = x
And, present age of his daughter is represented as = y
Seven years ago,
Aftab’s age = x – 7
Age of Aftab’s daughter = y – 7
According to the question,
(x – 7) = 7 (y – 7 )
x – 7 = 7 y – 49
x – 7y = – 49 + 7
x – 7y = – 42 … (i)
x = 7y – 42
Putting y = 5, 6 and 7, we get
x = 7 × 5 – 42 = 35 – 42 = – 7
x = 7 × 6 – 42 = 42 – 42 = 0
x = 7 × 7 – 42 = 49 – 42 = 7
Three years from now,
Aftab’s age = x + 3
Age of Aftab’s daughter = y + 3
According to the question,
(x + 3) = 3 (y + 3)
x + 3 = 3y + 9
x – 3y = 9 – 3
x – 3y = 6 … (ii)
x = 3y + 6
Putting, y = – 2, –1 and 0, we get
x = 3 × – 2 + 6 = – 6 + 6 =0
x = 3 × – 1 + 6 = – 3 + 6 = 3
x = 3 × 0 + 6 = 0 + 6 = 6
Algebraic representation
From equation (i) and (ii)
x – 7y = – 42 … (i)
x – 3y = 6 … (ii)
Graphical representation
2. The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.
Ans. Let cost of one bat be = Rs x
And, cost of one ball be = Rs y
3 bats and 6 balls are for Rs 3900
Therefore, 3x + 6y = 3900 … (i)
Dividing equation by 3, we get
x + 2y = 1300