Question

the pair of linear equation 2x^2+3y=5,4x+ky=10have infinitw number of solution if-​

Answer 1

Step-by-step explanation:

$\tt Let's \;solve\; for \;x.$

2x2+3y=5

Step 1: Add -3y to both sides.

2x2+3y+−3y=5+−3y

2x2=−3y+5

Step 2: Divide both sides by 2.

2x22=−3y+52

x2=−32y+52

Step 3: Take square root.

x=−32y+52 or x=−√−32y+52

Answer

$\tt:x=√−32y+52 or x=−√−32y+52$

Answer 2

Answer:

k=6 then pair will have infinite solutions