Question

the pair of linear equation 2x^2+3y=5,4x+ky=10have infinitw number of solution if-​

Answer 1

For the two lines a

1

x+b

1

y−c

1

=0 anda

2

x+b

2

y−c

2

=0 to have infinite solutions,

a

2

a

1

=

b

2

b

1

=

c

2

c

1

Here, the lines are 2x+3y−5=0 and 4x+ky−10=0

Thus,

4

2

=

3

k

=

10

5

⇒k=6

Answer 2

Answer:

k= 6

step by step explanation:

refer to the picture

for the equations to have infinite solutions,

a1/a2 =b1/b2 = c1/c2

1/2= 3/k

k= 2×3

k =6

Hope it helps you!!