the pair of linear equation 2x+3y=5,4x+ky=10have infinitw number of solution if
Answers
Answered by
2
Step-by-step explanation:
k=6
For the two lines a
1
x+b
1
y−c
1
=0 anda
2
x+b
2
y−c
2
=0 to have infinite solutions,
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Here, the lines are 2x+3y−5=0 and 4x+ky−10=0
Thus,
4
2
=
3
k
=
10
5
⇒k=6
Answered by
1
Answer:
there are unique solution
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