Math, asked by mr6203751, 3 months ago

the pair of linear equation 2x+3y=5,4x+ky=10have infinitw number of solution if​

Answers

Answered by Avishkar8353
2

Step-by-step explanation:

k=6

For the two lines a

1

x+b

1

y−c

1

=0 anda

2

x+b

2

y−c

2

=0 to have infinite solutions,

a

2

a

1

=

b

2

b

1

=

c

2

c

1

Here, the lines are 2x+3y−5=0 and 4x+ky−10=0

Thus,

4

2

=

3

k

=

10

5

⇒k=6

Answered by raykheresejal
1

Answer:

there are unique solution

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