Question

the pair of linear equation (3k + 1)x + 3Y - 5 = 0 and 2x - 3 Y + 5 = 0 have infinite solutions then find the value of k​

Answer 1

I hope this answer is right

Answer 2

Answer:

-1

Step-by-step explanation:

If the equation has infinitely many solutions then

a1/a2 = b1/b2 = c1/c2

(3k+1)/2 = 3/-3 = -5/5

(3k+1)/2 = -1

3k + 1 = -2

3k = -3

k=-3/3

k = -1