Question

the pair of linear equation 3x-5y=6 and 4x-3y=8 has a unique solution?​

Answer 1

By Substitution Method:-

(i) 3x-5y=6

=>3x=6+5y

$= > x = \frac{6 + 5y}{3} - - - (iii)$

(ii) 4x-3y=8

[Substituting the value of x from equation (iii) in equation (ii)]

$= > 4(\frac{6 +5y }{3}) - 3y = 8$

$= > \frac{24 + 20y}{3} - 3y = 8$

$= > \frac{24 + 20y - 9y}{3} = 8$

$= > 11y = 8 \times 3 - 24$

$= > y = \frac{24 - 24}{11} = \frac{0}{11}$

$= > y = 0$

[From equation (iii)]

$x = \frac{6 + 5y}{3}$

$= > 3x = 6 + 5 \times 0$

$= > x = \frac{6}{3} = 2$

Therefore, x=2, y=0.

Hope it helps (. ❛ ᴗ ❛.)

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