Math, asked by Happy2394, 11 months ago

The pair of linear equations 2x-3y=1 and 3x-2y=4 has

Answers

Answered by piya9346
23

Step-by-step explanation:

2x-3y=1

3x-2y=4

a1/a2= 2/3

b1/b2=-3/-2. ( (- ) (-) cancle so it remains 3/2)

c1/c2=1/4

a1/a2 = b1/b2 not equal to c1/c2 ( no solution)

Attachments:
Answered by JeanaShupp
20

The pair of linear equations 2x-3y=1 and 3x-2y=4 has one unique solution.

Explanation:

The given pair of linear equations :

2x-3y=1\\\\ 3x-2y=4

We know that ,

If for a pair of linear equation a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0

\dfrac{a_1}{a_2}\neq\dfrac{b_1}{b_2} , then it has a unique solution other wise not.

Since , \dfrac{2}{3}\neq\dfrac{3}{2} , it means the pair of linear equations has only one unique solution.

Hence, the pair of linear equations 2x-3y=1 and 3x-2y=4 has only one unique solution.

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