Question

the pair of linear equations 2x+3y-5=0and 4x+6y-10=0 is​

Answer 1

Answer:

0 is the answer

Step-by-step explanation:

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Answer 2

Answer:

The pair of linear equations has infinity many solutions.

Step-by-step explanation:

Given the pair of linear equations 2x+3y-5 = 0 and 4x+6y-10 = 0

The general equations are a1x + b1y + c1 = 0 and a2x+b2y+c2=0

2x +3y - 5 = 0    -------------(1)

comparing the coefficients then

a1 = 2, b1 = 3, c1 = -5

4x + 6y -10 = 0

a2 = 4, b2 = 6, c2 = -10.

Now

$\frac{a1}{a2} = \frac{2}{4} =\frac{1}{2}$

$\frac{b1}{b2} = \frac{3}{6} = \frac{1}{2}$

$\frac{c1}{c2} = \frac{-5}{-10} =\frac{1}{2}$

Therefore $\frac{a1}{a2} =\frac{b1}{b2} =\frac{c1}{c2}$

Therefore, the pair of linear equations has infinity many solutions.