The pair of linear equations (3k+1) x + 3y -5 = 0 and 2x – 3y +5 = 0 have
infinite solutions. Then the value of k is
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If the equation has infinitely many solutions then
a1/a2 = b1/b2 = c1/c2
(3k+1)/2 = 3/-3 = -5/5
(3k+1)/2 = -1
3k + 1 = -2
3k = -3
Therefore k = -1 ...
Hope this helps you...
a1/a2 = b1/b2 = c1/c2
(3k+1)/2 = 3/-3 = -5/5
(3k+1)/2 = -1
3k + 1 = -2
3k = -3
Therefore k = -1 ...
Hope this helps you...
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