Question

The pair of linear equations (3k+1) x + 3y -5 = 0 and 2x – 3y +5 = 0 have
infinite solutions. Then the value of k is

Answer 1

hope it will help u mate....

Answer 2

If the equation has infinitely many solutions then

a1/a2 = b1/b2 = c1/c2

(3k+1)/2 = 3/-3 = -5/5

(3k+1)/2 = -1

3k + 1 = -2

3k = -3

Therefore k = -1 ...


Hope this helps you...