The pair of linear equations (3k+1)x+3y-5 and 2x-3y+5=0 have infinity solutions. Then find the value of k.
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infinite solutions means
a1/a2=b1/b2=c1/c2
3k+1/2= 3/-3
3k+1= -2
k= -3/3
k= -1
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a1/a2=b1/b2=c1/c2
3k+1/2= 3/-3
3k+1= -2
k= -3/3
k= -1
please mark as brainlist
please mark it as brain list
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