the pair of linear equations 6x-ky-3=0, kx-24y-2=0 has a unique solution then find k
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Answer: For unique solution, K ≠ 4,48
Explanation:
Using the condition in the pic, we get,
6/k ≠ k/24 ≠ 3/2
Equating any two conditions,
6/k ≠ 3/2 => k ≠ 4
k/24 ≠ 3/2 => k ≠ 48
For unique solution, K ≠ 4,48
Explanation:
Using the condition in the pic, we get,
6/k ≠ k/24 ≠ 3/2
Equating any two conditions,
6/k ≠ 3/2 => k ≠ 4
k/24 ≠ 3/2 => k ≠ 48
For unique solution, K ≠ 4,48
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- Equating any two conditions,
- 6/k ≠ 3/2 => k ≠ 4
- k/24 ≠ 3/2 => k ≠ 48
- For unique solution, K ≠ 4,48
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