Question

the pair of linear equations 6x-ky-3=0, kx-24y-2=0 has a unique solution then find k

Answer 1

Answer:

let ,

the given system of linear equations are of the form

6x+ky=3     a₁x +b₁y+c₁ = 0                  

kx-24y=2     a₂x +b₂y+c₂ = 0

the condition for unique solution is a₁/a₂≠  b₁b₂

here ,

a₁ = 6, a₂ = k

b₁ = k,b₂ = -24

6/k ≠k/ -24

⇒6/k*-24≠k^2

  -144/k$\neq$k^2

root of 144/k=k

   12 root of k$\neq$k

hope it helps

tq............/////////

Step-by-step explanation: