Question

The pair of linear equations 8x – 4y + 7 = 0 and 2x – y – 16 = 0 has:

Unique solution

no solution

two solutions

infinitely many solutions

none

​

Answer 1

Answer:

unique solution. this linear equation has a unique numberical solution.

Answer 2

Answer:

$a1 = 8 \: \: \: \: \: \: b1 = - 4 \: \: \: \: \: \: c1 = 7 \\ a2 = 2 \: \: \: \: \: \: b 2= - 1 \: \: \: \: \: \: c2 = - 16 \\ \\ here \\ \frac{8}{2} = \frac{ - 4}{ - 1} = \frac{7}{ - 16} \\ \frac{a1}{a2} = \frac{b1}{b2} \: not = \frac{c1}{c2} \\ \\ therefore \: the \: pair \: of \: linear \: equation \: has \: no \: solutions$

Step-by-step explanation:

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