Question

The pair of linear equations x +y = 3 , 2x + 5y = 12
has a unique solution x = x1, y = y1, then value of x1,
(1) 1 (2) 2 (3)-1 (4) - 2
​

Answer 1

$\textbf{Given:}$

$x+y=3$

$2x+5y=12$

$\textbf{To find:}$

$\text{Solution of system of equations}$

$\textbf{Solution:}$

$\text{Since (x_1,y_1) is the solution of the given system, we have}$

$\bf\,x_1+y_1=3$

$\bf\,2x_1+5y_1=12$

$5x_1+5y_1=15$

$2x_1+5y_1=12$

$\text{Subtracting these equations we get}$

$3x_1=3$

$\implies\bf\,x_1=1$

$\therefore\textbf{The value of \bf\,x_1 is 1}$

$\text{Hence option (1) is correct}$

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