the pair of linear kx+2y=5 and 3x+y=1
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The two equations kx+2y=5and 3x+y=1 represents two straight lines. For the equations to possess no solution, they must be parallel and not coincident.
For this we must have:
∣∣∣k321∣∣∣=0
⟹k−6=0
⟹k=6
Look at the graph. It will be clearer.
Here the blue line represents 3x+y=1 and the red line 6x+2y=5.
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