The Palace of Peace and Accord in Astana, Kazakhstan, was built in 200620062006. The building has a right square-based pyramid structure. The length of a side of the square base is 62\,\text{m}62m62, start text, m, end text, and the vertical height of the pyramid is also 62\,\text{m}62m62, start text, m, end text.
What is the slant height \ellℓell of one of the triangular faces?
Answers
Answer:
The correct values in the question are:
year : 2006, length 62, vertical height 62.
So, the measure asked is called slant height . we have to apply the formula:
sh = √(vh^2 + [L/2]^2)
Where:
vh= vertical height
L= length of a side of the square base
Replacing with the values given:
sh= √(62^2 + [62/2]^2)
sh = √(3,844 + 31^2)
sh= √(3,844 + 961)
sh = √4,805
hs= 69.31 =69.3 m (nearest tenth)
Since in the question that height is called h, h= 69.3
Answer:
The correct values in the question are:year : 2006, length 62, vertical height 62.So, the measure asked is called slant height . we have to apply the formula:sh = √(vh^2 + [L/2]^2)Where: vh= vertical heightL= length of a side of the square baseReplacing with the values given:sh= √(62^2 + [62/2]^2)sh = √(3,844 + 31^2)sh= √(3,844 + 961)sh = √4,805hs= 69.31 =69.3 m (nearest tenth)Since in the question that height is called h, h= 69.3
Step-by-step explanation: