the palace sides of a Trapezium are 65 and 40 its non parallel sides are 39 metre and 56 metre find the area of the trapezium
Answers
Answered by
88
Answer:
x²+h² = 56²
(25-x)²+h² = 39²
x²-56² = (25-x)² - 39²
x = 224/5
So,
h² = 56²-x² = 28224/25
h = 168/5
Thus,
The area is (40+65)/2 × 168/5 = 1764
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dreamgirl1684:
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Answered by
17
Answer:
x+h2 = 562
(25-x)2+h2 = 392
x²-562 = (25-x)? - 392
x = 224/5
So,
h2 = 562-x2 = 28224/25
h = 168/5
Thus,
The area is (40+65)/2 x 168/5 = 1764
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