Question

the palm of Shyam hand has an area of 0.002. m² if the atmospheric pressure on the palm is 100000Pa what us the force being exerted on the shyams palm by atmosphere ??​

Answer 1

Answer:

• 200 newton is the required answer.

Explanation:

Given:-

• Area ,A = 0.002m²
• Atmospheric Pressure , P = 100000 Pa

To Find:-

• Force being exerted on the shyam's palm ,F

Solution:-

According to the Given Information

It is given that palm of Shyam hand has an area of 0.002 m². And the atmospheric pressure on the palm is 100000Pa. We have to calculate the force exerted by atmosphere on the shyam's palm .

As we know the relationship between Force , Area & Pressure.

• P = F/A

where,

• P denote Pressure
• F denote Force
• A denote Area

Substitute the value we get

→ 100000 = F/0.002

→ 100000 × 0.002 = F

→ F = 100000 × 0.002

→ F = 200 N

• Hence, the force exerted by atmosphere on the shyam's palm is 200 newton.

Answer 2

Answer:

Given :-

• The palm of Shyam hand has an area of 0.002 m².
• The atmospheric pressure on the palm is 100000 Pa.

To Find :-

• What is the force being exerted on the Shyam palm by atmosphere.

Formula Used :-

$\clubsuit$ Force Formula :

$\mapsto \sf\boxed{\bold{\pink{Force =\: Pressure \times Area}}}$

Solution :-

Given :

$\bigstar\: \: \rm{\bold{Pressure =\: 100000\: Pa}}$

$\bigstar\: \: \rm{\bold{Area =\: 0.002\: m^2}}$

According to the question by using the formula we get,

$\longrightarrow \sf Force =\: 100000 \times 0.002$

$\longrightarrow \sf Force =\: 100000 \times \dfrac{2}{1000}$

$\longrightarrow \sf Force =\: \dfrac{100000 \times 2}{1000}$

$\longrightarrow \sf Force =\: \dfrac{200\cancel{000}}{1\cancel{000}}$

$\longrightarrow \sf Force =\: \dfrac{200}{1}$

$\longrightarrow \sf\bold{\red{Force =\: 200\: Newton}}$

$\therefore$ The force being exerted on the Shyam palm by atmosphere is 200 Newton.

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EXTRA INFORMATION :-

❒ Force :

• Force is a push and pull upon an object.

❒ Pressure :

• Force acting on a unit area of a surface is called pressure.
• $\sf\bold{Pressure =\: \dfrac{Force}{Area}}$