The papulation of a town and a contant ground of 4%p.a ao its present population is 62.500 what will be its population after 2 year
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Principle = 62.500
Rate = 4%
Time =2 year
Amount = p(1+R/100)^n
A=62.500(1+4/100)^2
A= 62.500(1+1/25)^2
A=62.500(25+1/25)^2
A= 62.500×26/25×26/25
A=62500/1000×26/25×26/25
A= 67.6
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