the parallax of heavenly body measured from two points diametrically opposite on equator of the earth is 1 min.if the radius of the earth is 6400km,find the distance of the heavenly body from the center of the earth in AU.Given 1AU=1.5rast to power11
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30
Answer:
Step by Step solution:
The angle is given as 1 minute. We need to convert that into radians.
Hence, Ɵ = 1/60 * ∏ / 180
Diameter of the earth = l = 2 * radius of the earth = 2 * 6400 * 103 m
Distance of the heavenly body from the centre of the earth = r = l/ Ɵ
r = 2 * 6400 * 103 / 1/60 * ∏ / 180
= 2 * 6400 * 103 * 60 * 180 / ∏
= 4.4 * 1010 m
We know that 1 AU = 1.5 * 1011 m
Hence, r = 4.4 * 1010 / 1.5 * 1011 = 0.29 AU
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Answered by
4
Answer:
0.29 AU
Explanation:
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