Question

The parallel combination of two 10 ohm resistors are placed across the terminals of 24v battery (a) what is the effective resistance of The parallel circuit (b) what is the current through the entire circuit (c) what is the current through the branch of the circuit.

Answer 1

(a). Parallel combinations of 2 resistance of 10 ohms gives
1 / R = 1 / R1 + 1 / R2
1 / R = 1 / 10 + 1 / 10
1 / R = 2 / 10
R = 10 / 2
R = 5 ohms effective resistance

(b). PD = 24 V
V = IR
24 = 5 I
I = 4.8 Amps current through the circuit

(c). Current through each resistance is
24 = 10I
I = 24 / 10
I = 2.4 Amps

Answer 2

Answer:

5 ohms is the effective resistance of The parallel circuit.

The current through the entire circuit is 4.8 amp.

The current through the branch of the circuit is 2.4 amp.

Explanation:

As per the data given in the question

we have to calculate (a) what is the effective resistance of The parallel circuit (b) what is the current through the entire circuit (c) what is the current through the branch of the circuit.

As per the questions it is given that the parallel combination of two 10 ohm resistors are placed across the terminals of 24v battery.

(a) Parallel combinations of 2 resistance of 10 ohms gives :

we know that 1 / R = 1 / R1 + 1 / R2 (For parallel combinations)

1 / R = 1 / 10 + 1 / 10

1 / R = 2 / 10

R = 10 / 2

R = 5 ohms

Hence, 5 ohms is the effective resistance of The parallel circuit.

(b) Resistors are placed across the terminals of battery = 24 V

we know that V = IR

24 = 5 I

I = 4.8 amps

Hence, the current through the entire circuit is 4.8 amp.

(c) current through the branch of the circuit is

24 = 10I

I = 24 / 10

I = 2.4 amps

Hence, the current through the branch of the circuit is 2.4 amp.

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