the parallel side of a Trapezium are 10 cm and 6 cm long and the perpendicular distance between these two side is 4 cm find the area of this type is yam
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first we cut the trapzium into a rectangle and two triangle, ______6cm_____
/ | \
/ |4cm \
/_________ |________\
10cm
like this, _______6cm___
/| | | |\
/ | | 4cm| | \
/__| |_____________| |__\
2cm. 6cm. 2cm
join ∆s /|\
/ | \
/__|__\
4cm
area of ∆s= 1/2*b*h=1/2*4*4=8cm²
area of rectangle=l*b=6*4=24cm²
area of the tapzium=area of triagle+area of rectangle
=(8+24)cm²
=32cm²
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