Question

The parallel side of a trapezium are 30 cm and 20 cm and the distance between them is 15 cm find the area of trapezium.​

Answer 1

Answer:

area of trapeziym = 1/2(sum of parallel sides)× height.

= (1/2)×(30+20)×15

= [(1/2)×50×15]

= 375cm²Ans.

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Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}$

• The parallel side of a trapezium are 30 cm and 20 cm and the distance between them is 15 cm find the area of trapezium.

$\large\underline{ \underline{ \sf \maltese{ \: Diagram:- }}}$

$\setlength{\unitlength}{1.5cm}\begin{picture}\thicklines\qbezier(0,0)(0,0)(1,2.2)\qbezier(0,0)(0,0)(4,0)\qbezier(3,2.2)(4,0)(4,0)\qbezier(1.5,2.2)(0,2.2)(3,2.2)\put(0.8,2.4){ \bf A }\put(3,2.4){ \bf D }\put(-0.3,-0.3){ \bf B }\put(4,-0.3){ \bf C }\put(4.4,0){\vector(0,0){2.2}}\put( 4.4, 0){\vector(0,-1){0.1}}\put(4.6,1){ \bf 15\ cm }\put(0, -0.5){\vector(1,0){4}}\put(0, -0.5){\vector( - 1, 0){0.1}}\put(1.7, - 0.9){ \bf 30\ cm }\put(0.8, 2.8){\vector(1,0){2.5}}\put(0.8, 2.8){\vector( - 1, 0){0.1}}\put(1.7, 3){ \bf 20\ cm }\end{picture}$

$\large\underline{ \underline{ \sf \maltese{ \: Given :- }}}$

• 1 st Side = $\sf\green{ 20cm}$
• 2nd Side = $\sf\green{ 30cm}$
• Height = $\sf\green{ 15cm}$

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$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Area _{( \: Trapezium \: )} \: = \: \frac{1}{2} \: \times \:Sum \: of \: parallel \: sides \times \: Height }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\quad {:} \longrightarrow \sf{\sf{ \frac{1}{2} \: \times \: ( \: 20 \: + \: 30 \: ) \: \times \: 15sq.cm }}$

$\quad {:} \longrightarrow \sf{\sf{ \frac{1}{2} \: \times \: 50 \: \times \: 15sq.cm }}$

$\quad {:} \longrightarrow \sf{\sf{ \frac{1}{\cancel{2}} \: \times \: \cancel{50} \: \times \: 15sq.cm }}$

$\quad {:} \longrightarrow \sf{\sf{ \: 25 \: \times \: 15sq.cm }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Area_{(Trapezium)}\: = \: 375sq.cm }}}$

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$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Area \: of \: Trapezium \: = \underline {\underline{ 375sq.cm}}}\\\end{gathered}\end{gathered}$

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$\red{\boxed{ \sf \blue{ More \: for \: Knowledge }}}$

• Trapezium is a quadrilateral in which a pair of opposite side is parallel.
• Diagonal is a line segment which connects any two non- adjacent vertices in a polygon.
• Polygon is a simple closed curve that is made up of line segments.

Example of Polygon

1. Triangle
2. Quadrilateral
3. Pentagon
4. Hexagon

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