the parallel side of a trapezium are in the ratio 5:3 and the and the other side are 10 cm each if the perimeter of trapezium is 92 cm find the length of the parallel side and areas of the trapezium
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Answer:
3x = 36cm
& 5x = 60cm
Step-by-step explanation:
GIVEN:
A trapezium ABCD , DC // AB
DC : AB = 3:5 , So, If DC = 3x AB = 5x
Height CG of the trapezium = 16 cm
Area ( trapezium ABCD) = 768cm²
TO PROVE:
DC & AB
CONSTRUCTIONS:
D C. Cut AE = ince AE // DC
PROOF :
AECD is a parellelogram ( as one pair of opposite sides are equal & parallel)
= AE = 3x, EB = 2x
Area( parallelogram AECD) = side * corresponding height
=> 3x * 16 = 48x cm ² ………(1)
Area ( triangle CEB) = 1/2 * side * corresponding height.
Area( triangle CEB) = 1/2 * 2x * 16 = 16x cm²…(2)
Now by adding (1) +(2)
48x + 16x = 64x = 768
=> x = 768/64 = 12
So, 3x = 36cm
& 5x = 60cm
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