The parallel side of trapezium are 44 cm and 16 cm and the non parallel sides are 25 cm and 17 cm find the distance between parallel sides
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Solution:
Area of triangle = √s(s-a)(s-b)(s-c)
S = (28+25+17)/2
= 35
Area of triangle = √35(35 - 28)(35 - 25)(35 - 17)
= √35(7)(10)(18)
= √44100
= 210 sq cm
Area of the triangle = (1/2)×base×height
210 = (1/2) × 28 × h
h = 15
Hence, the distance between parallel sides is 15 cm.
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