Question

The parallel sides a trapezium are 16cm and 26 cm respectively and the non-parallel sides are equal to 13cm each. Find the area​

Answer 1

Answer:

height of trapezium = √169-25=√144

=12cm then area= 1/2× 16cm+26cm×12cm

=108cm^2

hope this helps!!

Answer 2

Answer:

HOPE THIS HELPS YOU AEMY

Step-by-step explanation:

Let ABCD is a trapezoid in which

Parallel sides AD=16 cm, BC=26 cm

And nonparallel sides AB=DC=13 cm

Draw AE and DF ⊥ BC at points E and F respectively such that AD=EF=16 cm, BE=FC=(26-16)/2=10/2=5 cm

In right angled triangle AEB and DFC

By Pythagoras Theorem,

AE²+EB²=AB² and DF²+FC²=DC²

Or, AE²+5²=13² and DF²+5²=15²

Or, AE²=169-25 and DF²=169-25

Or, AE²=144 and DF²=144

Or, AE²=12² and DF²=12²

Or, AE=12 cm and DF=12 cm

Area of the trapezoid = (AD+BC)/2×AE or DF

Or, Area of the trapezoid = 0.5×(AD+BC)×AE

Or, Area of the trapezoid = 0.5×(16+26)×12

Or, Area of the trapezoid = 0.5×42×12

Or, Area of the trapezoid = 252 cm²

Therefore, the area of the trapezoid = 252 cm²