Question

The parallel sides of a trapezium are 10 m and 20m.and the distance between them is 8 m. find the area

Answer 1

$\bf\underline{\underline{\purple{SOLUTION:-}}}$

Question

• The parallel sides of a trapezium are 10 m and 20m.and the distance between them is 8 m. find the area?

Answer

• Area of trapezium = 120m²

Given

• Parallel sides are 10m and 20m
• Height = 8m

To Calculate

• Area__?

Explanation

Parallel Sides are 10m and 20m ( Given )

Height = 8m

${\boxed{\red{\tt{Area \:of \: Trapezium = 1/2 (Sum \:of\: Parallel\: sides) ×h }}}}$

putting value,

➩ 1/2 ×(10+20)×8

➩1/2×30×8

➩ 1/2 ×30×4

➩ 120

➩ 120m²

$\bf\underline{\underline{\purple{HENCE:-}}}$

• Area of trapezium = 120m²

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Answer 2

Given Parameters : The parallel sides of a trapezium are 10 m and 20m.and the distance between them is 8 m.

_________________.....

Answer:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\linethickness{0.5mm}\qbezier(0, 0)(0,0)(1,3)\qbezier(5,0)(5,0)(4,3)\qbezier(1,3)(1,3)(4,3)\qbezier(0,0)(9.5,0)(1,0)\put( - 0.3,-0.2){ \sf A }\put(2.2,3.2){10 m}\put(5.1,-0.2){ \sf B }\put(2.1, - 0.5){20 m}\put(4.1,3){ \sf C }\put(0.6,3){ \sf D }\put(5.9, 0){\vector(0,0){3.1}}\put(6.5,1.8){\sf{height = 8m}}}\end{picture}$

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies \sf Area \: of \: trapezium = \dfrac{1}{2} \times Sum \: of \: parallel \: sides \times Height$

$:\implies \sf Area \: of \: trapezium = \dfrac{1}{2} \times (10 + 20) \times 8$

$:\implies \sf Area \: of \: trapezium = 30 \times 4$

$:\implies \underline{ \boxed{ \sf Area \: of \: trapezium = 120 \: {m}^{2}}}$

$\therefore\underline{\textsf{The area of trapezium is \textbf{120 m ^2 }}}$