Question

the parallel sides of a trapezium are 12 and 24 metre other two sides are equal each being 12 cm. can trapezium be considered as a sum of area of parallelogram and an isosceles triangle ? find the height of the base of isosceles triangle and area of trapezium ​

Answer 1

Area 1/2 (s1+s2) h
1/2 (12+24) *0.12
36/2*0.12
18*0.12
2.16m^2

Answer 2

Step-by-step explanation:

In the above diagram,

AYNS is a Trapezium which is divided into 2 Parellelogram (AMTS and MYNR) and an isosceles triangle (MTR).

M is the mid point of AY,

ST = RN,

AS || MT,

YN || MR,

Hence, Area of AYNS(Trapezium) can be considered as sum of AMTS, MYNR(Parellelogram) and MTR(Isosceles triangle).