Question

The parallel sides of a trapezium are 12 cm and 10 cm and perpendicular height is 7 cm. Find the area of this trapezium.​

Answer 1

Answer:

area of trapezium=1/2( l+ b) × h

" " = 1/2 ( 7cm+10cm)×12

" " = 1/2×17×12

" " = 1/2×204

" " = 102cm^2

(Note:1/2 is 1 upon 2 ok

and cm^2 in this the sing is nothing it is olny the cm square ok.) .

if you have dout now also the msg me I'll solve it again ok

Answer 2

Given:-

• Height of trapezium = 7 cm
• parallel sides of trapezium = 12cm and 10cm.

To find:-

• Find the area of the trapezium ?

Solutions:-

We have,

• The height of trapezium is 7cm
• parallel sides of trapezium are 12cm and 10cm.

We know that,

The area of trapezium = (sum of parallel side) × height

According to question:-

=> (12 + 10) × 7

=> 22 × 7

=> 154

Hence, the area of trapezium is 154cm².

Some Important:-

• Area of trapezium => 1/2(sum of parallel side) × height
• Perimeter = sum of all side.
• AB // CD
• <A + <D = <B + <C = 180°