The parallel sides of a trapezium are 12 cm and 24 cm. Its other two sides are equal, each being 12 cm. Can
trapezium be considered as a sum of area of parallelogram and an isosceles triangle ? Find the height to
the base of isosceles triangle and area of trapezium.
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Answer:
Length× breadh
= 12+12=24
24×24= 576cm is the answer.
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