Question

The parallel sides of a trapezium are 13 cm and 7 cm and the distance between them is 10

cm. The area of the trapezium is
please help​

Answer 1

$the \: 1st \: parallel \: side \: = 13cm \\ the \: 2nd \: parallel \: side = 7cm \\ height = 10cm \\ area \: of \: trapezium = \frac{1}{2} \times h \: (sum \: of \: parallel \: sides) \\ \frac{1}{2} \times 10 \: (13 + 7) \\ 5 \times 20 = 100 {cm}^{2}$

Note:- scroll from right to left to see the full solution

Answer 2

Given: The parallel sides of trapezium are 13 cm and 7 cm and the distance between them is 10 cm which is known as height of trapezium.

To Find: The area of trapezium

____________________________

Step-by-step explanation:

As we know that,

• Area of trapezium = ½ × (a + b) × h

$\\ \longrightarrow\sf{Area_{(trapezium)} = \frac{1}{2}\times(13+7)\times 10} \\ \\ \longrightarrow\sf{Area_{(trapezium)} = \frac{1}{ \cancel{2}} \times 20 \times \cancel{10}} \\ \\ \longrightarrow\sf{Area_{(trapezium)} =1 \times 20 \times 5} \\ \\ \\\longrightarrow\sf{Area_{(trapezium)} =100 \: {cm}^{2} }$

• Therefore,The area of trapezium is 100 cm².