Question

The parallel sides of a trapezium are 15cm and 8cm.if the distance between
them is 10 cm,what is the area of the trapezium?
​

Answer 1

AnswEr :

• The area of the trapezium = 115 cm².

Explanation :

We are given with the parallel sides of a trapezium and the distance between them, that is,

• Parallel sides of trapezium = 15cm and 8 cm.

• Distance between them = 10cm.

We have to find out the area of the trapezium$.$

As we are given with parallel sides of trapezium and distance between them we know the required formula, that is,

⠀

⠀

→ Area of trapezium = 1/2 × (sum of parallel sides) × Distance between them.

⠀

⠀

Substituting the given values in the formula,

⇒ Area of trapezium = 1/2 × (15 + 8) × 10

⇒ Area of trapezium = 1/2 × 23 × 10

⇒ Area of trapezium = 1 × 23 × 5

⇒ Area of trapezium = 23 × 5

⇒ Area of trapezium = 115

Hence, the area of the trapezium is 115 cm².

⠀

⠀⠀⠀ Additional information :

Know about trapezium :

• A trapezium is also a quadrilateral.

• A trapezium has defined shape.

• A trapezium has four unequal sides.

• A trapezium has two non parallel sides.

• The sum of all fourangles of a trapezium is 360°. This statement is known as angle sum property of trapezium.

Answer 2

✯ Given ✯

• Length of both parallel sides are 15 cm & 8 cm.
• Distance or height between them is 10 cm.

✯ To find ✯

• Area of Trapezium

✯ Formula ✯

${\underline{\boxed{ \bf{Area \: of \: a \: Trapezium= \frac{1}{2} \times ( Sum \: of \: parallel \: sides)\times Height }}}}$

✯ Solution ✯

☞${ \sf{Area \: of \: Trapezium = \cfrac{1}{2} \times( 15 + 8) \times 10}}$

☞ ${ \sf{Area \: of \: Trapezium = \cfrac{1}{2} \times( 23) \times 10}}$

☞ ${ \sf{Area \: of \: Trapezium = \cfrac{1}{\cancel 2} \times( 23) \times {\cancel{ 10}}}}$

☞ ${ \sf{Area \: of \: Trapezium = 1 \times 23 \times 5 }}$

☞ ${ \sf{Area \: of \: Trapezium = 23 \times 5}}$

${ \large{ \underline{ \boxed{ \red{ \sf{ Area \: of \: Trapezium = 115 \: {cm}^{2} }}}}}}$

Rough Diagram of Trapezium:-

$\setlength{\unitlength}{1.2 cm}\begin{picture}(0,0)\linethickness{0.5mm}\qbezier(0,0)(0,0)(1,3)\qbezier(5,0)(5,0)(4,3)\qbezier(1,3)(1,3)(4,3)\qbezier(3,0)(8.2,0)(0,0)\put(-0.5,-0.3){ \sf A }\put(5.3,-0.3){ \sf B }\put(4.2,3.1){ \sf C }\put(0.6,3.1){ \sf D }\end{picture}$

——————————————————————————

*Note :- For clear view of answer, See answer from web. Link is given below :-

https://brainly.in/question/30926616