Question

The parallel sides of a trapezium are 15m and 10m long and its non-parallel sides are 8m and 7m long.Find the area of the trapezium. ​

Answer 1

area of parallelogram =1÷2×(15 +10)×height

1÷2 ×25×7

=87.5

Answer 2

*base of the triangle formed with non parallel side=15-10=5m
*non parallel side = hypotenuse = 8m
${h}^{2} = {p}^{2} + {b}^{2} \\ {8}^{2} = {p}^{2} + {5}^{2} \\ 64 = {p}^{2} + 25 \\ 64 - 25 = {p}^{2} \\ 39 = {p}^{2} \\ \sqrt{39} = p \\ 6.24 = p$
p=height=6.24
$area \: of \: trapezium = > \frac{1}{2} \times height \times sum \: of \: parallel \: sides \\ \\ = \frac{1}{2} \times 6.24 \times (8 + 7) \\ \\ = 3.12 \times 15 \\ \\ = 46.8 {m}^{2}$