The parallel sides of a Trapezium are 20 m and 30 M and its non parallel sides are 6 metre and 8 metre find the area of trapezium
Answers
Answered by
23
There will be 2 triangles at the ends , since 20= 30-10m
remaining base =10m
if the triangle hypotenuse 6 has base x , hypotenuse 8 has base 10 -x and height h of the is
so,
h^2=6^2-x^2
h^2 = 8^2 -(10- x)^2
so,
36-x^2 =64 -(10-x ) ^2
36-x^2 = 64 -100+20x-x^2
72=20x
x=18/5m
h^2 =36- (18/5)^2
= 24/5m
area= 20 +30/2 × 24/ 5
=120 m^2
remaining base =10m
if the triangle hypotenuse 6 has base x , hypotenuse 8 has base 10 -x and height h of the is
so,
h^2=6^2-x^2
h^2 = 8^2 -(10- x)^2
so,
36-x^2 =64 -(10-x ) ^2
36-x^2 = 64 -100+20x-x^2
72=20x
x=18/5m
h^2 =36- (18/5)^2
= 24/5m
area= 20 +30/2 × 24/ 5
=120 m^2
Answered by
9
answer is 120m² by using formula
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