Math, asked by 19093, 4 days ago

The parallel sides of a trapezium are 20cm and 10cm, It's non parallel sides are 13cm each.Find it's area.​

Answers

Answered by allindia1630
3

We divide the trapezium into 3 parts: 2 triangles and a rectangle.

Base of triangle = 20−10 /2

=5

Height of the triangle and rectangle

=13^2 −5^2

⇒(h)^2 =144

⇒h = 12

Area of trapezium = 1/2 ×(sum of parallel sides) × (height)

= 1/2 × (10+20) × (12)

=180 sq.cm

This is correct answer

Answered by rituyadav88
1

Answer:

ABCD be the given trapezium in which AB = 20 cm, DC = AE= 13 cm, BC = 10 cm and AD = 10 cm. Through C, draw CE || AD, meeting AB at E. Draw CF ⊥ AB. ... Therefore, EF = ¹/₂ × EB = 1/2× 7 = 3.5 cm.

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