The parallel sides of a trapezium are 20cm and 10cm, It's non parallel sides are 13cm each.Find it's area.
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We divide the trapezium into 3 parts: 2 triangles and a rectangle.
Base of triangle = 20−10 /2
=5
Height of the triangle and rectangle
=13^2 −5^2
⇒(h)^2 =144
⇒h = 12
Area of trapezium = 1/2 ×(sum of parallel sides) × (height)
= 1/2 × (10+20) × (12)
=180 sq.cm
This is correct answer
Answered by
1
Answer:
ABCD be the given trapezium in which AB = 20 cm, DC = AE= 13 cm, BC = 10 cm and AD = 10 cm. Through C, draw CE || AD, meeting AB at E. Draw CF ⊥ AB. ... Therefore, EF = ¹/₂ × EB = 1/2× 7 = 3.5 cm.
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