Question

The parallel sides of a trapezium are 20cm and 13cm and distance between
parallel sides is 16cm. Find its area.​

Answer 1

Step-by-step explanation:

Height=16cm

Base 1=13 cm

Base 2=20 cm

so, area of trapezium =1/2×h(base 1+ base 2)

1/2×16(20+13)

8(20+13)

8×33

264cm^2

Answer 2

Answer:

Area of a TRAPEZIUM = h ($\frac{a + b}{2}$)

Height given = 16cm

Measures of 2 parallel sides = 20 cm and 13 cm

h ($\frac{a + b}{2}$) = 16 ($\frac{20 + 13}{2}$) = 16 x $\frac{33}{2}$ <Cancellation> = 8 x 33 = 264cm²

Hence, area of the trapezium = 264cm²

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