the parallel sides of a trapezium are 25 and 13 and its non parallel sides are 10 find it's area
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The area of a trapezium is given by,
Apply Brahmagupta (598–665) formula, A = [(s-a)(s-b)(s-c)(s-d)]^0.5 where s = [a+b+c+d]/2. Here s = [25+13+10+10]/2 = 58/2 = 29.
A = [(29–25)(29–13)(29–10)(29–10)]^0.5 = [4*16*19*19]^0.5 = 152 sq cm.
Dsnyder:
By pytogoras theorm DE= 8cm
Area of the Trapezium = 1/2*h(a+b) sq cm
Area of the Trapezium = 1/2*8(25+13)sq cm =152 sq cm
Area of the Trapezium = 1/2*8(25+13)sq cm =152 sq cm
how 8 came
pythogoras theorm
oh do you have what's app
ya bt i wont give to anyone
no I didn't mean that actually I want to understand it clearly are u an indian
nope
austrian
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area of trapezium = 1/2 * 10 * ( 25 + 13 )
= 5 * 38 = 190 sq units
= 5 * 38 = 190 sq units
it's the wrong
okk
mine also came this
wrong
I which class you read cutpriyanshi
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