The parallel sides of a trapezium are 25 cm
ind 13 cm, its non-parallel sides are equal,
cach being 10 cm. Find the area of the
trapezium
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Parallel sides are 25 cm and 13 cm.
Given, non parallel sides are equal.
Given, AB is 25 cm.
Let us construct DE and CF as heights.
So, AE and FB will be 6 cm, and EF will be 13 cm.
Now, to find the area of a Trapezium we have to find the height.
Taking one of the triangle and using pythagoras theorem, it's possible.
Consider triangle DAE,
h² + 6² = 10²
h² = 100 - 36
h = root of 64
h = 8 cm
Now, just use the formula to find the area of a tapezium,
I.e., 1/2h ( a + b )
--> 1/2 × 8 (25 + 13)
--> 4(38)
--> 152 cm²
Area of trapezium is 152 cm².
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