the parallel sides of a trapezium are 28 cm and 21 cm and each of the non parallel sidesis 17 cm find the area of the trapezium
Answers
Answered by
0
The figure is an isosceles trapezium because the non-parallel sides are both 17 CM.
28-21/2= 3.5cm
Distance between the parallel sides=( 17^2– 3.5^2)^0.5= 138.375 cm
Area of the isosceles trapezium =(28+21)*(138.375/2)= 49*69.1875
=3390 sqcm
28-21/2= 3.5cm
Distance between the parallel sides=( 17^2– 3.5^2)^0.5= 138.375 cm
Area of the isosceles trapezium =(28+21)*(138.375/2)= 49*69.1875
=3390 sqcm
Similar questions