Question

The parallel sides of a trapezium are 32 m and 20 m and the distance between them is 15 m then the area of trapezium is:

Answer 1

$<b>Hi !$

Here is your answer !!

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Parallel sides of the trapezium = 32 m and 20 m

Height = 15 m

Area = ?

$a \: = \: \frac{1}{2} \: \times \: ( \: b1 \: + \: b2 \: ) \: \times \: h \\ \\ = > \: \frac{1}{2 } \: \times \: ( \: 32 \: + \: 20 \: ) \: \times \: 15 \\ \\ = > \: \frac{1}{2} \: \times \: 52 \: \times \: 15 \\ \\ = > \: 26 \: \times \: 15 \\ \\ = > \: 390 \: {m }^{2} \: \: \: \: \: \: \: \: \: \: \: \: ans$

Ans ) The area of the trapezium is 390 m²

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Thanks !!

Answer 2

Here's your answer

Given :-
Parallel sides = 32m and 20m

Height = 15m

to find :-
Area of trapezium

Solution:-
area = 1/2 × sum of parallel sides × height

= 1/2 × (32+20) × 15

= 1/2 × 52 × 15

= 26 × 15

= 390 m²

UR ANS IS 390m²

HOPE THIS HELPS YOU❤❤