Question

the parallel sides of a trapezium are 3cm 5 cm if the distance between them is 2cm its area is​

Answer 1

Answer:

If the length of the parallel sides of a trapezium are 8 cm,9 cm and the distance between the parallel sides is 6 cm, then its area is 

A

51 cm2

B

68 cm2

C

34 cm2

D

72 cm2

Answer

Given: Length of parallel sides are 9cm and 5cm

Height =8cm

Area of trapezium=21× Height ×(Sum of parallel sides)

=21×8cm×(9+5)cm

=28+14cm2

=56cm2.

SECOND METHOD

Answer

Correct option is

Correct option isA

Correct option isA51 cm2

Correct option isA51 cm2Length of parallel sides=8 cm, 9 cm

Correct option isA51 cm2Length of parallel sides=8 cm, 9 cmDistance between parallel sides=6 cm

Correct option isA51 cm2Length of parallel sides=8 cm, 9 cmDistance between parallel sides=6 cmArea =21 (distance between parallel sides)× (sum of parallel sides)

Correct option isA51 cm2Length of parallel sides=8 cm, 9 cmDistance between parallel sides=6 cmArea =21 (distance between parallel sides)× (sum of parallel sides)=21×6×(8+9)=3×17=51

Answer 2

$\frak{Given}\:\begin{cases}\:\quad \sf The \:Parallel \:Sides \:of \:Trapezium \:are\:=\:\pmb{\frak{ 3 \:cm }}\:\&\:\pmb{\frak{5\:cm\:}}\:.\:\\ \:\quad \sf \:Distance \:between \:Parallel \:sides \:is\:=\:\pmb{\frak{ 2 \:cm}}\:.\end{cases}\:$

Need To Find : Area of Trapezium ?

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⠀⠀▪︎⠀We've Provided with the Parallel Sides of Trapezium & Distance between parallel sides of Trapezium. Now, We'll Area of Trapezium using the Formula to find Area of Trapezium .

⠀⠀

》 Formula for Area of Trapezium :

$\qquad \star\:\pmb{\underline {\boxed {\frak {\:Area_{\:(Trapezium)\:}\:=\:\dfrac{1}{2}\:\times h \:\bigg\lgroup \: a + b \bigg\rgroup \:\:sq.units\:}}}}\:$

⠀⠀⠀⠀⠀⠀Here , h is the Distance between parallel sides & a and b are Parallel sides of Trapezium.

$\qquad \dag{\underline {\frak { Substituting \:known \:Values \:in \:Formula \::\:}}}$

$:\implies \sf \:Area_{\:(Trapezium)\:}\:=\:\dfrac{1}{2}\:\times h \:\bigg\lgroup \: a + b \bigg\rgroup \:$

$:\implies \sf \:Area_{\:(Trapezium)\:}\:=\:\dfrac{1}{2}\:\times 2 \:\bigg\lgroup \: 3 + 5 \bigg\rgroup \:$

$:\implies \sf \:Area_{\:(Trapezium)\:}\:=\:\dfrac{1}{2}\:\times 2 \:\times \:8 \:$

$:\implies \sf \:Area_{\:(Trapezium)\:}\:=\:\dfrac{1}{\cancel {2}}\:\times \cancel {2} \:\times \:8 \:$

$:\implies \sf \:Area_{\:(Trapezium)\:}\:=\: \:8 \:$

$:\implies \pmb {\underline {\boxed {\purple {\:\frak{ \:Area_{\:(Trapezium)\:}\:=\: \:8 \:cm^2\:}}}}}\:\bigstar \:$

⠀⠀⠀⠀⠀∴ Hence, Area of Trapezium is 8 cm² .