Question

the parallel sides of a trapezium are 40 CM and 20 CM. it's non- parallel sides are both equal each being 26 CM find the area of trapezium​

Answer 1

Answer:

The parallel sides of an isosceles trapezium = 40 cm and 20 cm.

The equal sides = 26 cm.

The distance between the parallel sides = [26^2-{(40–20)/2}^2]^0.5

= [676–10^2]^0.5

= (676–100)^0.5

= 576^0.5

= 24 cm.

Area of trapezium = (40+20)*24/2 = 720 sq cm

Hope this will help you