the parallel sides of a trapezium are 40cm and 20cm. if its non parallel sides are both equal, each being 26 cm, find the area of the trapezium
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Answer:
The parallel sides of an isosceles trapezium = 40 cm and 20 cm.
The equal sides = 26 cm.
The distance between the parallel sides = [26^2-{(40–20)/2}^2]^0.5
= [676–10^2]^0.5
= (676–100)^0.5
= 576^0.5
= 24 cm.
Area of trapezium = (40+20)*24/2 = 720 sq cm.
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