The parallel sides of a trapezium are 46cm and 25cm. Its non- parallel sides are 20cm and 13 cm. Find the distance between the parallel sides and the area of the trapezium.
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Answer:
the distance between the parallel sides=12 cm
area=426 cm²
Step-by-step explanation:
In the ΔCAP
h²=20²-x²......(1)
in ΔDBQ
h²=13²-y²...............(2)
20²-x²=13²-y².
400-169=x²- y².
but x+y=AB-CD=46-25=21
y=21-x
so x²-(21-x)²=231
x²-(441-42x+x²)=231
-441+42x=231
42x=672
x=672/42=16
from(1)
h²=400-16²=400-256=144
h=12
the distance between the parallel sides=12 cm
so the area=(46+25)*12/2
=6*71
area=426 cm²
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