Question

the parallel sides of a trapezium are 5m and 8m and the perpendicular distance between them is 10m find the area of the trapezium
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Answer 1

Answer:

65m

Step-by-step explanation:

Area=1/2*h(a+b)

=1/2*10(5+8)

=1/2*10*13

=65m

Answer 2

AnswEr-:

$\sf{\bf{Given-:}}$

• The parallel sides of a trapezium are 5m and 8m

• Height or perpendicular distance between them is 10m.

$\sf{\bf{To\:Find-:}}$

• Area of Trapezium.

$\mathrm {\bf{ \dag{Solution \:of\:Question \:-:}}}$

$\underbrace {\mathrm {\bf{ Understanding \:the\:Concept \;-:}}}$

• We have to find the Area of Trapezium When Parallel Sides and Perpendicular Distance Between them [Height] is Given .

• Now by Putting known Values [ Parallel Sides and Perpendicular Distance Between them (Height) ] in the Formula for Area of Trapezium.

• By This we can get the Area of Trapezium.

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$\mathrm {\bf{ \dag{Finding \:Area\:of\:Trapezium \:-:}}}$

As , We know that ,

• $\underline{\boxed{\star{\sf{\purple{Area\:of \:Trapezium \:-:\frac {1}{2} \times Height \times ( a + b) \:or\:sum\:of\:Parallel\:Sides\:sq.units}}}}}$

$\sf{\bf{Here-:}}$

• The sum parallel sides of a trapezium or ( a +b) are (5+8) m

• Height or perpendicular distance between them is 10m.

Now By Putting known Values in Formula for Area of Trapezium-:

• $\qquad \quad \qquad \quad \longmapsto {\mathrm { Area \: = \dfrac{1}{2} \times 10 \times ( 5 + 8) }}$

• $\qquad \quad \qquad \quad \longmapsto {\mathrm { Area \: = \dfrac{1}{2} \times 10 \times 13 }}$

• $\qquad \quad \qquad \quad \longmapsto {\mathrm { Area \: = \dfrac{1}{\cancel {2}} \times \cancel {10} \times 13 }}$

• $\qquad \quad \qquad \quad \longmapsto {\mathrm { Area \: = 5 \times 13 }}$

• $\qquad \quad \qquad \quad \underline {\boxed{\pink{\mathrm { Area \: = 65 \:m^{2} }}}}$

Hence ,

• $\underline{\star {\mathrm{\red { Area\:of\:Trapezium \:is\: = 65\:m^{2} }}}}$

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$\large { \boxed {\mathrm |\:\:{\underline {More \:To\:Know\:-:}}\:\:|}}$

• Area of Rectangle = Length × Breadth sq.units

• Area of Square = Side × Side sq.units

• Area of Triangle = ½ × Base × Height sq.units

• Area of Trapezium = ½ × Height × ( a +b ) or Sum of Parallel sides sq.units

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