Question

the parallel sides of a trapezium are 65 cm and 49 cm and each of the non-parallel sides is 10 cm. find the area of the trapezium​

Answer 1

Answer:

decide trap. into 2 and recatangle

h2=b2+p2

(10)2=(8)2+p2

p2=100-64

h=6

area =1/2 *base*height

1/2*114*8

=456cm

Answer 2

Given:-

• Parallel sides of Trapezium are 65 cm and 49 cm.
• Measure of non parallel side i.e height of trapezium is 10 cm.

To Find:-

• Find the area of trapezium ?

Solution:-

• Let ABCD be a trapezium.

Where,

• AB = 65 cm
• DC = 49 cm
• DE = 10 cm (Height)
• AB || DC

We know that,

Area of Trapezium = 1/2 (Sum of parallel sides) × (Distance between them)

=> 1/2 ( AB + DC ) × ( DE )

=> 1/2 ( 65 + 49 ) × 10

=> 5 × 114

=> 570 cm²

Hence, the area of trapezium is 570 cm².

Some Important:-

• Area of Isosceles Trapezoid = (1/2) h (AB+CD)

Properties of a Trapezium

• The sum of all the four angles of the trapezium is equal to 360°.
• A trapezium has two parallel sides and two non-parallel sides.
• The diagonals of regular trapezium bisect each other.
• The length of the mid-segment is equal to half the sum of the parallel bases, in a trapezium.
• Two pairs of adjacent angles of a trapezium formed between the parallel sides and one of the non-parallel side, add up to 180 degrees.