Question

The parallel sides of a trapezium are 6cm and 10cm long .If the distance between the parallel sides is 5 cm, find the area of the trapezium

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\frak {Given} \begin{cases} &\sf{Sides\ of\ the\ trapezium\ =\ 6cm\ and\ 10cm.} \\ &\sf{Distance\ between\ parallel\ sides\ =\ 5cm.} \end{cases}$

To find:- We have to find the area of the trapezium ?

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$\frak{\underline{\underline{\dag As\ we\ know\ that:-}}}$

$\sf : \implies {Area\ of\ trapezium\ =\ \dfrac{1}{2}\ \times\ (Sum\ of\ parallel\ sides)\ \times\ (Distance\ between\ them).}$

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$\frak{\underline{\underline{\dag By\ substituting\ the\ values,\ we\ get:-}}}$

$\sf : \implies {Area\ of\ trapezium\ =\ \dfrac{1}{2}\ \times\ (Sum\ of\ parallel\ sides)\ \times\ (Distance\ between\ them)} \\ \\ \\ \sf : \implies {\dfrac{1}{2}\ \times\ (6\ +\ 10)\ \times\ 5} \\ \\ \\ \sf : \implies {\dfrac{1}{\cancel {2}}\ \times\ \cancel {16}\ \times\ 5} \\ \\ \\ \sf : \implies {8\ \times\ 5} \\ \\ \\ \sf : \implies {40cm^2} \\ \\ \\ \sf : \implies {\pink{\underline{\boxed{\bf Area\ =\ 40cm^2.}}}}\bigstar$

Hence:-

$\sf \therefore {\underline{The\ required\ area\ of\ the\ trapezium\ is\ 40cm^2.}}$