Question

the parallel sides of a trapezium are in the ratio 2:3 and the area of the trapezium is 125 CM square distance between the parallel lines is 10 cm find the length of the parallel sides of the trapezium

Answer 1

length of first parallel side is2x
length of second parallel side is 3x

ACCORDING TO QUESTION

area of trapezium = 1/2×h×(a+b)
125cmsq. =1/2×10×(2x+3x)
125cm sq. =5×(2x+3x)
125cm sq. = 10x+15x
125cm sq. = 25x
125/25. =x
5cm. =x

the length of first parallel side will be 2x = 5×2=10cm
the length of second parallel side will be 3x=3×5=15cm

Answer 2

Answer:

10 cm and 15 cm

Step-by-step explanation:

Let the parallel sides of a trapezium be 2x and 3x respectively.

Area of trapezium = 125 cm²

According to the question ;

Area of trapezium = $\frac{1}{2}$ * (sum of || sides ) * h

⇒ Area of trapezium = $\frac{1}{2}$* (2x + 3x) * 10

⇒ 125  = 5 ( 2x + 3x )

⇒ 5x = 125 / 5

⇒ 5x = 25

⇒ x = 25 / 5

⇒ x = 5

Therefore, parallel sides are ;

2x = 2 * 5 = 10 cm

3x = 3 * 5 = 15 cm