The parallel sides of a Trapezium are in the ratio 2:5 and the distance between the parallel sides is 10 cm if the area of the trapezium is 350 CM square find the length of its parallel sides
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Let one side be(a)=2x
another side be(b)= 5x and height (h)=10cm.
Area of trapezium =350cm^2 .
i e.h/2(a+b)=350
10/2(2x+5x)=350
5(7x)=350
there fore x=10
One side (2x)=2*10=20
another side (5x)=5*10=50.
another side be(b)= 5x and height (h)=10cm.
Area of trapezium =350cm^2 .
i e.h/2(a+b)=350
10/2(2x+5x)=350
5(7x)=350
there fore x=10
One side (2x)=2*10=20
another side (5x)=5*10=50.
Mayanksingh22960:
Let one side be 2x
Another side be 5xandheight=10vm
Area of trapezium =350cm².
2(a+b)
10/2(2x+5x)=350
5(7x)=350
Therefore x=10
One side 2*10=20
Another side (5x)=5*10=50
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0
2x and 5x are the parallel sides.
(1/2)(7x)(10)=350
x=10.
Therefore, parallel sides, 2x=20
5x=50
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