Question

The parallel sides of a trapezium are in the ratio 3:4 and the perpendicular distance between them is 12 cm. If the area of the trapezium is 630 cm2, thenfind itsshorter of the parallel sides

Answer 1

Answer:parallel sides of trapezium =  3 : 4 

height =  12 cm

area =  630 cm^2

let parallel sides of trapezium =  3x and 4x

area of trapezium = 

   630 cm^2 = 

    x  =  630 / 42 

         =  15 

 parallel sides are =  4 * 15 =  60 cm

                               3 * 15  = 45 cm 

Read more on Brainly.in - https://brainly.in/question/80238#readmore

Step-by-step explanation: